武汉大学版无机化学课后习题答案(第三版)(下册)

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Cu(NO3)2 + 2NaOH = Cu(OH)2 + 2NaNO3 Cu(OH)2 + 2HF = CuF2 + 2H2O

(5) ZnS + 2HCl + n H2O = ZnCl2nH2O + H2S

ZnCl2 nH2O = ZnCl2 + n H2O

(6) 3Hg + 8HNO3 = 3Hg(NO3)2 + 2NO ↑+ 4H2O

Hg(NO3)2 + 4KI = K2[HgI4] + 2KNO3 (7) ZnCO3 + H2SO4 = ZnSO4 + CO2 ↑+ H2O

2ZnSO4 + 2H2O = 2Zn +O2↑ + H2SO4

(8) Ag(S2O3)23- + 8Cl2 + 10H2O = AgCl↓ + 15Cl- + 4SO42- + 2OH-

AgCl + 2NH3 = [Ag(NH3)2]Cl

[Ag(NH3)2]Cl + HCOOH = Ag↓ + CO2 ↑+ H2O + NH3 ↑+ HCl 2[Ag(NH3)2]+ + Zn = 2Ag↓ + [Zn(NH3)4]2-

2[Ag(NH3)2]+ + CH3CHO + 2OH- = CH3COONH4 + 2Ag↓ + 3NH3 ↑+ H2O

6. 试设计一个不用H2S而能使下述离子分离得方案 Ag+, Hg2, Cu2+, Zn2+, Cd2+, Hg2+和Al3+ 答

混合溶液

HCl ║

AgCl,Hg2Cl2 Cu2+,Zn2+,Cd2+,Hg2+,Al3+

NH3?H2O KI(过量)

HgNH2Cl +Hg Ag(NH3)2+ CuI Zn2+,Cd2+,HgI42-,Al3+ NH3?H2O HgNH2I,HgNH2Cl,Al(OH)3 Zn(NH3)42+, Cd(NH3)42+

NaOH ║Δ

Zn(OH)2 ,Cd(OH)2 HgNH2I,HgNH2Cl Al(OH)4- NaOH

2-

Cd(OH)2 Zn(OH)4

7. 将1.008克铜—铝合金样品溶解后,加入过量碘离子,然后用0.1052mol·dm-3Na2S2O3溶液滴定生成得碘,共消耗29.84cm-3Na2S2O3溶液,试求合金中铜得质量分数。 解: 2Cu2+ + 2I- = CuI + I2

I2 + 2S2O32- = S4O62- + 2I-

2Cu2+与I2, 2S2O32- 相当

21

2?

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