µÚÆßÕÂÃ÷²Ûºã¶¨Á÷¶¯_Ë®Á¦Ñ§ ÏÂÔØ±¾ÎÄ

ÄÚÈÝ·¢²¼¸üÐÂʱ¼ä : 2025/11/4 21:55:24ÐÇÆÚÒ» ÏÂÃæÊÇÎÄÕµÄÈ«²¿ÄÚÈÝÇëÈÏÕæÔĶÁ¡£

µÚÆßÕ Ã÷²Ûºã¶¨Á÷¶¯

1¡¢»º±äÁ÷Ò»¶¨ÊÇ»ºÁ÷£¬¼±±äÁ÷Ò»¶¨ÊǼ±Á÷¡£ ( ) 2¡¢ÀâÖùÐÎÃ÷ÇþÖÐÐÎ³É S2 ÐÍË®ÃæÇúÏßʱ£¬Æä¸¥À͵ÂÊý Fr ÑØ³Ì¼õС¡£ ( ) 3¡¢S2 ÐÍË®ÃæÇúÏßÊÇ·¢ÉúÔÚ ( ) (1) »ºÆÂÇþµÀÖеĻºÁ÷ (2) ¶¸ÆÂÇþµÀÖеĻºÁ÷

(3) »ºÆÂÇþµÀÖеļ±Á÷ (4) ¶¸ÆÂÇþµÀÖеļ±Á÷

4¡¢ÔÚÃ÷Çþ½¥±äÁ÷ÖÐ ( ) (1)×ÜˮͷÏßÒ»¶¨Æ½ÐÐÓÚµ×ÆÂÏß (2)×ÜˮͷÏßÓë×ÔÓÉË®ÃæÏàÖØºÏ (3)²âѹ¹ÜˮͷÏßÓë×ÔÓÉË®ÃæÒ»Ö (4)Ë®ÃæÏßÓëµ×ÆÂÏ߯½ÐÐ

5¡¢·¢ÉúˮԾµÄ³ä·Ö±ØÒªÌõ¼þÊÇ ( ) (1)´Ó²ãÁ÷¹ý¶Éµ½ÎÉÁ÷ (2)´Ó¶¸ÆÂ¹ý¶Éµ½»ºÆÂ (3)´Ó»ºÁ÷¹ý¶Éµ½¼±Á÷ (4)´Ó¼±Á÷¹ý¶Éµ½»ºÁ÷

6¡¢ÒÑ֪ijˮբÏÂÓÎÊÕËõ¶ÏÃæË®Éî hc0 = 0.6 m (ÏàÓ¦µÄÔ¾ºóË®Éî hc0? = 3.5 m) ,ÁÙ½çË®Éî hc = 1.6 m£¬ÏÂÓκӵÀË®Éî t = 1.4 m ,ÔòբϽ«·¢Éú ( ) (1)Ô¶ÀëˮԾ (2) ÁÙ½çˮԾ (3) ÑÍûˮԾ (4) ¼±Á÷

7¡¢Ã÷ÇþÖз¢ÉúM3¡¢S3¡¢H3¡¢A3 ÐÍË®ÃæÇúÏßʱ£¬Æä¸¥À͵ÂÊý Fr ( ) (1)СÓÚ1 (2)µÈÓÚ1 (3)´óÓÚ1 (4)ÎÞ·¨È·¶¨ 8¡¢ÓÐÁ½ÌõÌÝÐζÏÃæÇþµÀ 1ºÍ 2£¬ÒÑÖªÆäÁ÷Á¿¡¢±ßÆÂϵÊý¡¢²ÚÂʺ͵׿í¾ùÏàͬ£¬µ«µ×ÆÂ i1 > i2 ,ÔòÆä¾ùÔÈÁ÷Ë®Éî h01 ºÍ h02 µÄ¹ØÏµÎª ( ) (1)h01 > h02 (2)h01 < h02 (3)h01 = h02 (4)ÎÞ·¨È·¶¨ 9¡¢ÓÐÁ½ÌõÌÝÐζÏÃæÇþµÀ 1 ºÍ 2£¬ÒÑÖªÆäÁ÷Á¿¡¢±ßÆÂϵÊý¡¢µ×ÆÂºÍ²ÚÂʾùÏàͬ£¬µ«µ×¿í b1 > b2 ,ÔòÆä¾ùÔÈÁ÷Ë®Éî h01 ºÍ h02 µÄ¹ØÏµÎª ( ) (1)h01´óÓÚh02 (2)h01СÓÚh02 (3)ÏàµÈ (4)ÎÞ·¨È·¶¨

10¡¢ÓÐÁ½ÌõÌÝÐζÏÃæÇþµÀ 1 ºÍ 2£¬ÆäÁ÷Á¿¡¢±ßÆÂϵÊý¡¢µ×¿í¼°µ×ÆÂ¾ùÏàͬ£¬µ«²ÚÂÊn1 > n2£¬ÔòÆä¾ùÔÈÁ÷Ë®Éîh01 ºÍ h02 µÄ¹ØÏµÎª ( ) (1)h01´óÓÚ h02 (2)h01СÓÚ h02 (3)ÏàµÈ (4) ÎÞ·¨È·¶¨

11¡¢ÓÐËÄÌõ¾ØÐζÏÃæÀâÖùÐÎÇþµÀ£¬Æä¹ýË®¶Ï̾̾»ý¡¢²ÚÂÊ¡¢µ×ÆÂ¾ùÏàͬ£¬Æäµ×¿í b Óë¾ùÔÈÁ÷Ë®Éî h¡£ÓÐÒÔϼ¸ÖÖÇé¿ö£¬Ôòͨ¹ýÁ÷Á¿×î´óµÄÇþµÀÊÇ ( ) (1) b1 =4 m £¬ h01 =1m (2) b2 =2 m £¬ h02 = 2m (3) b3 = 2.83 m £¬ h03 = 1.414m (4) b4 = 2.67 m £¬ h04 = 1.5m

12¡¢¾ØÐÎÃ÷ÇþË®Á÷ÖУ¬¶ÏÃæµ¥Î»ÄÜÁ¿ Es ÓëÊÆÄÜ h Ö®±ÈÖµ Es/h =1.8ʱ£¬Ë®Á÷µÄ¸¥À͵ÂÊý Fr Ϊ ( ) (1) Fr >1.0 (2) Fr <1.0 (3) Fr =1.0 (4) ²»¶¨

13¡¢M2ÐÍË®ÃæÇúÏß·¢ÉúÔÚ____ÆÂÉÏ£¬ÆäË®Á÷ÊôÓÚ_____Á÷¡£ÇúÏßµÄÌØÕ÷ÊÇ_____________________________ ______________________________¡£ 14¡¢Á½ÌõÀâÖùÐÎÃ÷ÇþµÄ¶ÏÃæÐÎ×´¡¢³ß´ç¡¢µ×ÆÂºÍͨ¹ýµÄÁ÷Á¿¾ùÏàͬ£¬µ«²ÚÂʲ»Í¬( n1 > n2)¡£ËüÃǵÄÕý³£Ë®Éîh01 ___h02 ;ÁÙ½çË®Éî hc1 ___hc2 ¡£

15¡¢Ë®µøÊÇË®Á÷´Ó____Á÷¹ý¶Éµ½____Á÷µÄ¾Ö²¿Ë®Á¦ÏÖÏó¡£µ±Á÷Á¿Ò»¶¨Ê±£¬µø¿²´¦µÄË®ÉîµÈÓÚ_______¡£

16¡¢Ë®Ô¾ÊÇË®Á÷´Ó_____Á÷¹ý¶Éµ½_____Á÷µÄ¾Ö²¿Ë®Á¦ÏÖÏó£»µ±Á÷Á¿Ò»¶¨£¬Ô¾Ç°Ë®ÉîÔö´óʱ£¬Ô¾ºóË®ÉîµÄ±ä»¯ÊÇ____________¡£

17¡¢ÔÚÃ÷ÇþË®Á÷ÖУ¬·¢Éú____ÐÍË®ÃæÇúÏßʱ£¬¶ÏÃæµ¥Î»ÄÜÁ¿ Es ÑØ³ÌÔö´ó£»·¢Éú____ÐÍË®ÃæÇúÏßʱ£¬Es ÑØ³Ì¼õС¡£(¸÷¾ÙÒ»Àý)

18¡¢ÈôÃ÷Çþ¾ùÔÈÁ÷Ë®Éî h0 =3m£¬ÏàÓ¦Á÷Á¿µÄÁÙ½çË®Éîhc=1.5m£¬Ôò¸¥À͵ÂÊýFrµÄ·¶Î§Îª_________________¡£ ÈôÁ÷Á¿²»±ä£¬²ÚÂÊ n Ôö´ó£¬ÔòFr ______¡£

19¡¢ÔÚ½øÐÐÃ÷Çþ½¥±äÁ÷Ë®ÃæÇúÏß¼ÆËãʱ£¬¶ÔÓÚ____Á÷£¬¿ØÖƶÏÃæÓ¦Ñ¡ÔÚÉÏÓΣ»¶ÔÓÚ____Á÷£¬¿ØÖƶÏÃæÓ¦Ñ¡ÔÚÏÂÓΡ£ 20¡¢Í¼Ê¾ÎªÒ»ÀâÖùÐÎÃ÷Çþ£¬Á½¶ÎÇþµÀµÄ¶ÏÃæÐÎ×´¡¢³ß´ç¼°µ×ÆÂ¾ùÏàͬ£¬µ«²ÚÂʲ»Í¬ (n1 < n2)¡£ÔòÆäÕý³£Ë®Éî h01 ºÍ h02 µÄ±È½ÏÊÇ__________£¬ÁÙ½çË®Éîhc1ºÍ hc2 µÄ±È½ÏÊÇ____________,ÁÙ½çµ×ÆÂic1ºÍ ic2 µÄ±È½ÏÊÇ _______ _______¡£ 2

21¡¢ÀâÖùÐÎÃ÷Çþºã¶¨½¥±äÁ÷»ù±¾Î¢·Ö·½³Ì d h/d s =(i-J )/(1-Fr)±íʾˮÉî h ÑØ³Ì±ä»¯¹æÂÉ£¬Æä·Ö×Ó·´Ó³Ë®Á÷µÄ ___________________£¬·Öĸ·´Ó³Ë®Á÷µÄ____________________________¡£

??

22¡¢Æ½µ×ÀâÖùÐÎÃ÷ÇþµÄˮԾº¯ÊýΪ______________________________,ˮԾµÄǰºóË®ÉîÒÔ h ºÍ h ±íʾ£¬ÔòÓÐˮԾº¯Êý¹ØÏµÊ½_________________________¡£

23¡¢Ã÷ÇþË®Á÷µÄ¸¥À͵ÂÊý Fr ±íʾˮÁ÷µÄ_____Á¦Óë_____Á¦×÷ÓÃÖ®±È£¬¿É×÷ΪÅбðÁ÷̬µÄ±ê×¼£¬µ±Ë®Á÷Ϊ¼±Á÷ʱ£¬_____Á¦×÷ÓÃΪÖ÷£¬Fr ______£¬µ±Ë®Á÷Ϊ»ºÁ÷ʱ£¬_____Á¦×÷ÓÃΪÖ÷£¬Fr ______¡£

24¡¢¶¨ÐÔ»æ³öͼʾÀâÖùÐÎÃ÷ÇþµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßÃû³Æ¡£(¸÷Çþ¶Î¾ù³ä·Ö³¤£¬¸÷¶Î²ÚÂÊÏàͬ)

37

25¡¢¶¨ÐÔ»æ³öͼʾÀâÖùÐÎÃ÷ÇþµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßÃû³Æ¡£(¸÷Çþ¶Î¾ù³ä·Ö³¤£¬¸÷¶Î²ÚÂÊÏàͬ)

26¡¢¶¨ÐÔ»æ³öͼʾÁ½¶Î¿í¶È²»Í¬µÄÀâÖùÐÎÃ÷ÇþµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßÃû³Æ¡£(¸÷Çþ¶Î¾ù³ä·Ö³¤£¬¸÷¶Î²ÚÂÊ Ïàͬ)

27¡¢¶¨ÐÔ»æ³öͼʾÀâÖùÐÎÃ÷ÇþµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßÃû³Æ¡£(¸÷Çþ¶Î¾ù³ä·Ö³¤£¬¸÷¶Î²ÚÂÊÏàͬ)

28¡¢¶¨ÐÔ»æ³öͼʾÀâÖùÐÎÃ÷ÇþµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßÃû³Æ¡£(¸÷Çþ¶Î¾ù³ä·Ö³¤£¬¸÷¶Î²ÚÂÊÏàͬ)

29¡¢ÏÂÁÐÁ½Í¼ÖÐËù»æË®ÃæÏßÊÇ·ñÕýÈ·£¬ÊÔ·ÖÎö¸ÄÕýÖ®¡£ 30¡¢¿í¾ØÐÎÇþµÀÓÉÈý¶Î×é³É£¬¾ùΪ³¤Çþ£¬Èý¶ÎÇþµÀµ×¿í¾ùÏàµÈ¡£ABÇþ¶Î²ÚÂÊΪn1£¬BCÇþ¶Î²ÚÂÊΪn2£¬CDÇþ¶Î²ÚÂÊΪ n3£¬n1 < n3 ic)¡£¶¨ÐÔ»æÖÆË®ÃæÏߣ¬²¢×¢Ã÷Ë®ÃæÏßÀàÐÍ¡£

31¡¢Ë®¿â¾­³¤Ð¹ºé¶´Ð¹ºé£¬Ð¹ºé¶´¶ÏÃæÎª¾ØÐΣ¬¶´ÄÚË®Á÷ΪÎÞѹÁ÷£¬Æä×ÝÆÊÃæÈçͼËùʾ¡£¶´ºó½ÓÒ»µÈ¿íµÄ ¾ØÐ㤶¸ÆÂ£¬³ö¿ÚΪƽµ×¾ØÐÎÏûÄܳء£ÊÔ¶¨ÐÔ»æ³öË®ÃæÇúÏߣ¬²¢±êÃ÷Ðͺš£

hc0 : ÊÕËõ¶ÏÃæË®É ic :ÁÙ½çµ×ÆÂ; hc : ÁÙ½çË®É d : ÏûÄܳسØÉî¡£

38

3

32¡¢Ò»¿í¶È b=1.0 m µÄ¾ØÐζÏÃæÀâÖùÐÎÇþµÀ£¬Í¨¹ýÁ÷Á¿ qv =3.13 m/sʱ£¬Õý³£Ë®Éî h0=1.5 m¡£ÒªÇó£º (1)Åбð¸ÃÇþµÀµ×ÆÂÊôÓÚ»ºÆÂ¡¢¶¸ÆÂ»òÁÙ½çÆÂ£»

(2)²âµÃij¶ÏÃæË®Éî h=1.25 m£¬Åбð¸Ã´¦Ë®Á÷Ϊ»ºÁ÷»ò¼±Á÷£¬ÇþÖз¢ÉúºÎÖÖË®ÃæÇúÏߣ¬»æ³öÆäͼÐΡ£

33¡¢µ×ÆÂ i=0.01µÄµÈ¿í¾ØÐζÏÃæÇþµÀ£¬ÄÚÊ¢¾²Ë®¡£½ñÔÚÏà¾à ?s=100 m Á½¸ö¶ÏÃæ²âµÃË®Éî·Ö±ðΪ h1=2 m ¼°h2= 3 m ¡£ÊÔµ¼³ö΢²¨²¨ËÙ C Ëæ¾àÀë S ±ä»¯µÄ¹ØÏµÊ½£¬²¢Çó³ö²¨´Ó¶ÏÃæ1µ½¶ÏÃæ2ËùÐèµÄʱ¼ä t ¡£ ( 20.3s )

2

34¡¢ÓÐÒ»ÌÝÐζÏÃæÇþµÀ£¬µ×ÆÂ i=0.0005£¬±ßÆÂϵÊý m=1,²ÚÂÊ n=0.027£¬¹ýË®¶Ï̾̾»ý A£½10 m¡£ÇóË®Á¦×î¼Ñ¶ÏÃæ¼°ÏàÓ¦µÄ×î´óÁ÷Á¿¡£Èô¸ÄΪ¾ØÐζÏÃæ£¬ÈÔÓûά³ÖÔ­ÓÐÁ÷Á¿£¬ÇÒÆä²ÚÂʼ°µ×ÆÂ i ¾ù²»±ä£¬ÎÊÆä×î¼Ñ³ß´çÈçºÎ? ( h=2.34m; b=1.94m; 9.19m3 /s; h=2.26m; b=4.53m )

35¡¢ÂÛÖ¤Ã÷Çþ¾ùÔÈÁ÷ʱˮÁ¦ÆÂ¶È¡¢²âѹ¹ÜˮͷÏßÆÂ¶È¡¢µ×ÆÂÏàµÈ£¬¼´ J = Jp= i ¡£

36¡¢ÊÔ¾Ù³öÔÚÃ÷ÇþÖз¢ÉúÁÙ½çË®ÉîµÄÁ½¸öʵÀý£¬²¢ÓÃͼ±êÃ÷ÁÙ½çË®ÉîµÄλÖá£

9/201/10/(n9/10g1/2) ʽÖÐ i Ϊµ×ÆÂ£»n Ϊ²ÚÂÊ£»q Ϊµ¥37¡¢ÊÔÖ¤¿ídz¾ØÐζÏÃæÇþµÀÖк㶨¾ùÔÈÁ÷ʱ¸¥À͵ÂÊý Fr?iq¿íÁ÷Á¿£»g ÎªÖØÁ¦¼ÓËÙ¶È¡£

38¡¢¶ÏÃæµ¥Î»ÄÜÁ¿ Es ºÍµ¥Î»ÖØÁ¿ÒºÌå×ÜÄÜÁ¿ E ÓÐÊ²Ã´Çø±ð?Ã÷Çþ¾ùÔÈÁ÷ Es ºÍ E ÑØÁ÷ÊÇÔõÑù±ä»¯µÄ?Ã÷Çþ·Ç¾ùÔÈÁ÷ EsºÍ E ÑØÁ÷ÊÇÔõÑù±ä»¯µÄ?

39¡¢ºÎν¶ÏÃæµ¥Î»ÄÜÁ¿?ÊÔÐðÊö¶ÏÃæµ¥Î»ÄÜÁ¿ÇúÏßµÄÌØÕ÷¡£

39

40¡¢ÓÐÒ»ÓÉÁ½¶Î²»Í¬µ×ÆÂ i1 ºÍ i2 µÄÇþµÀÏàÁ¬½ÓµÄÀâÖùÐÎÃ÷Çþ£¬ÇþµÀ¶ÏÃæÎª¾ØÐΣ¬¿í¶È b=3 m¡£µ±Í¨¹ýÁ÷Á¿ qv=

3

15 m/s ʱ£¬ÒÑÖª i1 ºÍ i2 Çþ¶ÎµÄÕý³£Ë®Éî·Ö±ðΪ h01=0.7 m£¬h02 =2 m¡£ÒªÇó£º (1)ÅбðÉÏ¡¢ÏÂÓÎÇþµÀ¸÷ΪºÎÖÖµ×ÆÂ£» (2)È·¶¨Ë®Ô¾·¢ÉúÔÚÄÄÒ»Çþ¶ÎÉÏ£»

(3)¶¨ÐÔ»æ³öÇþµÀµÄË®ÃæÇúÏߣ¬²¢×¢Ã÷ÇúÏßµÄÃû³Æ¡£ 41¡¢Í¼Ê¾ÎªÒ»½¥±äÀ©É¢Çþ¶Î AB Á¬½Ó¶þÀâÖùÐγ¤Çþ¡£ÒÑÖªÇþµÀ¶ÏÃæÎª¾ØÐΣ¬ÉÏÓÎÇþ¿í b1 =3 m£¬Õý³£Ë®Éîh01=1.8 m£¬

3

ÏÂÓÎÇþ¿í b2=4 m£¬Õý³£Ë®Éî h02=2 m£¬½¥±ä¶Îµ×ÆÂ i=0£¬ÉÏÓζ˶ÏÃæA´¦Ë®Éî h=1.94 m; ÇþÖÐÁ÷Á¿qv=10 m/s¡£ÒªÇ󻿳öË®ÃæÇúÏßÏà½Óͼ£¬²¢×¢Ã÷ÀâÖùÐÎÇþ¶ÎµÄË®ÃæÇúÏßÀàÐÍ¡£

42¡¢Í¼Ê¾ÎªËÄÖÖ¹ýË®¶ÏÃæÐÎ×´²»Í¬µÄÃ÷Çþ£¬µ«Æä¹ýË®¶Ï̾̾»ý¡¢²ÚÂÊ¡¢µ×ÆÂ¾ùÏàͬ£¬ÊÔÂÛÖ¤²¢±È½Ï¸÷Ã÷Çþͨ¹ýÁ÷Á¿µÄ´óС¡£ ( qd?qa?qc?qb )

43¡¢Ö¤Ã÷¼±Á÷ͨ¹ý¾ØÐζÏÃæÃ÷ÇþÖеÄÕϰ­Îïʱ£¬Õϰ­ÎïÉϵÄË®Ãæ±ØÈ»ÉÏÉý¡£¼´Í¼ÖÐh1 ?h2?a¡£

44¡¢ÊÔ·ÖÎöÒÔÏÂÈýÖÖË®ÃæÏß·¢ÉúµÄ¿ÉÄÜÐÔ£¬ÈçÄÜ·¢Éú£¬Çë˵Ã÷·¢ÉúµÄÌõ¼þ£¬ÇúÏßÃû³Æ·ûºÅ¼° h1 ºÍ h2 µÄȡֵ´óС»ò·¶Î§¡£

40

2

45¡¢Í¼Ê¾ÎªÒ»¾ØÐζÏÃæÆ½µ×Ã÷ÇþÖеÄˮԾ£¬Ë®Ô¾µ×²¿ÓÐÒ»µÍ¿²¡£ÒÑÖªµ¥¿íÁ÷Á¿ q = 6 m/s ¡£Ô¾Ç°Ë®Éî h1 = 0.5m£¬Ë®Á÷×÷ÓÃÔÚµ¥¿íµÍ¿²ÉϵÄ×ÜѹÁ¦R??(?gh12)/2¡£È¡¶¯Á¿Ð£ÕýϵÊýΪ1¡£ (1)ÇóÔ¾ºóË®Éîh2£» (h2?3.55m£»Î޵Ϳ²Ê± h2=3.59m ) (2)´ËÔ¾ºóË®ÉîÓëÎ޵Ϳ²Ê±µÄÔ¾ºóË®ÉîÏà±È£¬Äĸö´ó?´ó¶àÉÙ?

46¡¢ÒÑÖªÌÝÐζÏÃæÇþµÀµÄµ×¿í b=1m£¬±ßÆÂϵÊý m=1¡£ÔÚˮƽÇþ¶ÎÉϵÄˮԾ¹²éîË®ÉîΪ h1=0.2 m£¬h2=0.6 m£¬Çóͨ¹ýÇþµÀµÄÁ÷Á¿ qv¡£[ÌÝÐζÏÃæÐÎÐĵÄÉî¶È hc=h(3b?2bh)/6(b?mh)] (qv?0.849m3/s )

3

47¡¢Ä³¾ØÐζÏÃæÆ½µ×ÇþµÀ£¬µ×¿í b=7 m£¬Í¨¹ýÁ÷Á¿ qv=40 m/s¡£ÈôÇþÖз¢ÉúˮԾʱ£¬Ô¾Ç°Ë®Éî h1=0.8 m¡£Çó¸ÃˮԾµÄˮͷËðʧ¡£ (v2=40/(7?2.5)=2.28m/s£»?E?0.64m )

348¡¢ÌÝÐζÏÃæÈÀÍÁÇþµÀ£¬ÒÑ֪ͨ¹ýÁ÷Á¿Q?10.5m/s£¬µ×¿íb?8.9m£¬±ßÆÂϵÊým?1.5£¬Õý³£Ë®Éîh0?1.25m£¬²ÚÂÊn?0.025£¬Çóµ×ÆÂiºÍÁ÷ËÙv¡£ ( i=0.000377 ,v=0.78m/s )

349¡¢ÓÐÒ»¹à¸È¸ÉÇþ£¬¶ÏÃæÎªÌÝÐΣ¬µ×¿íb?2.2m£¬±ßÆÂϵÊým?1.5£¬Êµ²âÁ÷Á¿Q?8.11m/sʱ£¬¾ùÔÈÁ÷Ë®Éî

h0?2m£¬ÔÚ1800m³¤µÄ˳ֱÇþ¶ÎË®ÃæÂä²î?h?0.5m£¬ÇóÇþµÀµÄ²ÚÂÊn¡£ (n=0.0228 )

50¡¢Ò»Ê¯ÇþµÄ±ßÆÂϵÊým?0.1£¬²ÚÂÊn?0.020£¬µ×¿íb?4.3m£¬Ë®Éîh?2.75m£¬µ×ÆÂi?1/2000£¬ÇóÁ÷Á¿ºÍ

41